-30x^2-6x+24=0

Solution for -30x^2-6x+24=0 equation:

-30x^2-6x+24=0

a = -30; b = -6; c = +24;
Δ = b2-4ac
Δ = -62-4·(-30)·24
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-54}{2*-30}=\frac{-48}{-60}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+54}{2*-30}=\frac{60}{-60}
=-1
$